6cos^2(2x)-5cos(2x)+1=0

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Solution for 6cos^2(2x)-5cos(2x)+1=0 equation:


Simplifying
6cos2(2x) + -5cos(2x) + 1 = 0

Remove parenthesis around (2x)
6cos2 * 2x + -5cos(2x) + 1 = 0

Reorder the terms for easier multiplication:
6 * 2cos2 * x + -5cos(2x) + 1 = 0

Multiply 6 * 2
12cos2 * x + -5cos(2x) + 1 = 0

Multiply cos2 * x
12cos2x + -5cos(2x) + 1 = 0

Remove parenthesis around (2x)
12cos2x + -5cos * 2x + 1 = 0

Reorder the terms for easier multiplication:
12cos2x + -5 * 2cos * x + 1 = 0

Multiply -5 * 2
12cos2x + -10cos * x + 1 = 0

Multiply cos * x
12cos2x + -10cosx + 1 = 0

Reorder the terms:
1 + -10cosx + 12cos2x = 0

Solving
1 + -10cosx + 12cos2x = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -10cosx + -1 + 12cos2x = 0 + -1

Reorder the terms:
1 + -1 + -10cosx + 12cos2x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -10cosx + 12cos2x = 0 + -1
-10cosx + 12cos2x = 0 + -1

Combine like terms: 0 + -1 = -1
-10cosx + 12cos2x = -1

Reorder the terms:
1 + -10cosx + 12cos2x = -1 + 1

Combine like terms: -1 + 1 = 0
1 + -10cosx + 12cos2x = 0

The solution to this equation could not be determined.

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